Consider a sequence xn -4cos 2 n -4 - Then what is the average power of the above signal -

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Standard XII

Mathematics

Second Fundamental Theorem of Calculus

Consider a se...

Question

$C o n s i d e r a s e q u e n c e x (n) = 4 cos (\frac{2 n π}{4})$ . Then what is the average power of the above signal ______.
8

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Solution

The correct option is A 8

The period of above signal is $N = 4$
The signal in one period is $x (n) = 4, 0, - 4, 0$
The average power of x(n) is
$P = \frac{1}{N} N - 1 \sum n = 0 | x (n) |^{2}$

$= \frac{1}{4} (16 + 16) = \frac{32}{4} = 8$

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Consider a sequence x(n)=4cos(2nπ4). Then what is the average power of the above signal ______.8

The correct option is A 8 The period of above signal is N=4 The signal in one period is x(n)=4,0,−4,0 The average power of x(n) is P=1NN−1∑n=0|x(n)|2 =14(16+16)=324=8

$C o n s i d e r a s e q u e n c e x (n) = 4 cos (\frac{2 n π}{4})$ . Then what is the average power of the above signal ______.
8

The correct option is A 8

The period of above signal is $N = 4$
The signal in one period is $x (n) = 4, 0, - 4, 0$
The average power of x(n) is
$P = \frac{1}{N} N - 1 \sum n = 0 | x (n) |^{2}$

$= \frac{1}{4} (16 + 16) = \frac{32}{4} = 8$