Question

Consider a series RLC circuit for which $R=150\Omega ,L=20mH,V_{rms}=20V,\omega =5000s^{-1}$ . Determine the value of the capacitance for which the current is a maximum.

• A. $.25\mu F$
• B. $0.75\mu F$
• C. $1\mu F$
• D. $2\mu F$

Answer 1

The correct option is D $2\mu F$

current is maximum at resonance
$\omega =\frac{1}{\sqrt{LC}}\Rightarrow 5000=\frac{1}{\sqrt{.02\times C}}\Rightarrow C=2\mu F$