Consider a situation as shown in figure. Find the minimum value of m so that the blocks do not move.
A
2kg
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B
8kg
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C
10kg
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D
1kg
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Solution
The correct option is B8kg For equilbrium, N=(10+m)g,T=6g Friction force, f=μN=13[10+m]g for the blocks to remain at rest, T=f and f≤μN ⇒6g≤(10+m)g3⇒18≤(10+m)⇒m≥8kg