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Question

Consider a solution having [H+]=105 M at 25C, then OH ion concentration of this solution at the given temperature is :

A
105 M
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B
109 M
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C
1010 M
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D
108 M
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Solution

The correct option is B 109 M
pH=log[H+]pH=log(105)pH=5
pH+pOH=14
pOH=145=9
log[OH]=9
[OH]=109


Theory:
pKw:
pKw at 25oC is pKw = log10(1.0×1014) = 14
Since pH = log10[H+] and pOH = log10[OH]
Kw = [H+][OH] log10Kw = (log10[H+])+(log10[OH])
pKw = pH + pOH,
14=pH+pOH


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