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Question

Consider a sparingly soluble salt, zirconium phosphate [Zr3(PO4)4]. If molar solubility of zirconium phosphate is denoted by s and its solubility product by Ksp , then which of the following relationship holds true?

A
s=(Ksp144)17
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B
s=(Ksp144)7
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C
s=(Ksp6912)17
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D
s=(Ksp6912)7
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Solution

The correct option is C s=(Ksp6912)17
The dissociation equation at equilibrium is :

[(Zr)3(PO4)4](s)3Zr4+(aq)+4PO34(aq)Equilibrium: Cs 3s 4s

Solubility of Zirconium Phosphate = s
[Zr4+]=3s
[PO34]=4s
Ksp=[Zr4+]3[PO34]4

Ksp=(3s)3×(4s)4

Ksp=6912×s7

s=(Ksp6912)17

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