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Byju's Answer
Standard XII
Mathematics
Coordinates of a Point in Space
Consider a sp...
Question
Consider a sphere passing through the origin and the points
(
2
,
1
,
−
1
)
,
(
1
,
5
,
−
4
)
,
(
−
2
,
4
,
−
6
)
.
What is the radius of the sphere?
A
√
12
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B
√
14
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C
12
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D
14
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Solution
The correct option is
B
√
14
Equation of sphere is
x
2
+
y
2
+
z
2
+
2
x
−
4
y
+
6
z
=
0
Put the value
(
0
,
4
,
0
)
, we get
0
+
16
+
0
+
0
−
16
+
0
=
0
So the sphere passes through the point
(
0
,
4
,
0
)
Thus radius of sphere is
√
1
4
Suggest Corrections
0
Similar questions
Q.
Consider a sphere passing through the origin and the points
(
2
,
1
,
−
1
)
,
(
1
,
5
,
−
4
)
,
(
−
2
,
4
,
−
6
)
.
What is the centre of the sphere?
Q.
Consider a sphere passing through the origin and the points
(
2
,
1
,
−
1
)
,
(
1
,
5
,
−
4
)
,
(
−
2
,
4
,
−
6
)
.
Consider the following statements:
1
. The sphere passes through the point
(
0
,
4
,
0
)
.
2
. The point
(
1
,
1
,
1
)
is at a distance of
5
unit from the centre of the sphere.
Which of the statements is
/
are correct?
Q.
Three solid spheres of radii 6 cm, 8 cm and 10 cm are melted to form a sphere. The radius of the sphere so formed is
(a) 24 cm
(b) 16 cm
(c) 14 cm
(d) 12 cm
Q.
The centre of the circle passing through the points
(
8
,
12
)
,
(
11
,
3
)
and
(
0
,
14
)
is
Q.
What is the surface area of a sphere if the radius is
14
c
m
?
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