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Standard VII

Mathematics

Equal Angles Subtend Equal Sides

Consider a sq...

Question

Consider a square $A B C D$ of side $12$ and let $M, N$ be the midpoints of $A B, C D$ respectively. Take a point $P$ on MN and let $A P = r, P C = s$ . Then the area of the triangle whose sides are $r, s, 12$ is

72

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36

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\frac{r s}{2}

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\frac{r s}{4}

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Solution

The correct option is B $36$
Since PD=PC=s,PA=r,AD=12
Therefore we will find the area of $Δ$ APD
$Δ A P D = \frac{1}{2} \times 12 \times 6$
$= 36$

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Consider a square ABCD of side 12 and let M,N be the midpoints of AB,CD respectively. Take a point P on MN and let AP=r,PC=s. Then the area of the triangle whose sides are r,s,12 is

The correct option is B 36Since PD=PC=s,PA=r,AD=12Therefore we will find the area of ΔAPDΔAPD=12×12×6=36

Consider a square $A B C D$ of side $12$ and let $M, N$ be the midpoints of $A B, C D$ respectively. Take a point $P$ on MN and let $A P = r, P C = s$ . Then the area of the triangle whose sides are $r, s, 12$ is

The correct option is B $36$
Since PD=PC=s,PA=r,AD=12
Therefore we will find the area of $Δ$ APD
$Δ A P D = \frac{1}{2} \times 12 \times 6$
$= 36$