Diagonals of a Parallelogram Divides It into Two Congruent Triangles
Consider a sq...
Question
Consider a square ABCD that has a diagonal BD. What will be the measure of each angle of the △ABD formed?
A
∠ABD=40° ∠BDA=40° ∠DAB=100°
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B
∠ABD=55° ∠BDA=35° ∠DAB=90°
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C
∠ABD=40° ∠BDA=50° ∠DAB=90°
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D
∠ABD=45° ∠BDA=45° ∠DAB=90°
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Solution
The correct option is D∠ABD=45° ∠BDA=45° ∠DAB=90° We know that each angle of a square is 90°. Also the diagonal of a square bisects the angles at its vertices.
∴∠ABD=∠DBC=∠CDB=∠BDA=45°
Hence, the measure of the angles of the triangle △ABD is ∠ABD=45° ∠BDA=45° ∠DAB=90°