Consider a standard negative feedback configuration withGs-1s-1s-2 and Hs-s-s- For the closed loop system to have poles on the imaginary axis- the value of - should be equal to up to one decimal place

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Consider a standard negative feedback configuration with
$G (s) = \frac{1}{(s + 1) (s + 2)} a n d H (s) = \frac{s + α}{s} .$ For the closed loop system to have poles on the imaginary axis, the value of $α$ should be equal to (up to one decimal place)

9

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Solution

The correct option is A 9
$G (s) = \frac{1}{(s + 1) (s + 2)}; H (s) = \frac{s + α}{s}$

For poles on imaginary axis i.e.
Marginal stability,

$α = 3 \times 3 = 9$

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Consider a standard negative feedback configuration with G(s)=1(s+1)(s+2) and H(s)=s+αs. For the closed loop system to have poles on the imaginary axis, the value of α should be equal to (up to one decimal place) 9

The correct option is A 9G(s)=1(s+1)(s+2);H(s)=s+αs For poles on imaginary axis i.e. Marginal stability, α=3×3=9

Consider a standard negative feedback configuration with
$G (s) = \frac{1}{(s + 1) (s + 2)} a n d H (s) = \frac{s + α}{s} .$ For the closed loop system to have poles on the imaginary axis, the value of $α$ should be equal to (up to one decimal place)

9

The correct option is A 9
$G (s) = \frac{1}{(s + 1) (s + 2)}; H (s) = \frac{s + α}{s}$

For poles on imaginary axis i.e.
Marginal stability,

$α = 3 \times 3 = 9$