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Question

# Consider a straight conductor of length 2m. Carrying a current of 10 A in the +z direction. If the conductor is placed in a field of →B=0.02(^ay−^ax)Wb/m2 , then the force on per unit length of the conductor is

A
0.4(^ax+^ay) N/m
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B
0.4(^ax^ay) N/m
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C
0.2(^ax+^ay) N/m
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D
0.2(^ax+^ay) N/m
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Solution

## The correct option is C −0.2(^ax+^ay) N/m (c) →F=I(→L×→B) = 10(2^az×0.02(^ay−^ax) = 10(0.04(−^ax)−0.04^ay) = −0.4^ax−0.4^ay Force acting per unit length, →FL=−0.4^ax−0.4^ay2 = −0.2^ax−0.2^ay →FL = −0.2(^ax+^ay)

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