Consider a strong base- CaOH2 in a solution having concentration of 0-5-10-5 M- The pH of the given solution of CaOH2 is -

Given, [Ca(OH)_2]_initial=0.5×10^ 5 M=C Since it is a strong base, it ionizes completely. nbsp; Then , nbsp; Ca(OH)_2(aq)⇌ Ca^2+(aq.)+2OH^ (aq.) Initial: ...

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Standard XI

Chemistry

pH the Power of H

Consider a st...

Question

Consider a strong base, $C a (O H)_{2}$ in a solution having concentration of $0.5 \times 10^{- 5} M$ . The $p H$ of the given solution of $C a (O H)_{2}$ is :

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Solution

The correct option is C 9
Given, $[C a (O H)_{2}]_{i n i t i a l} = 0.5 \times 10^{- 5} M = C$
Since it is a strong base, it ionizes completely.
Then ,

$C a (O H)_{2} (a q) ⇌ C a^{2 +} (a q .) + 2 O H^{-} (a q .) I n i t i a l : C 00 E q u i l i b r i u m : 0 C 2 C$

$[O H^{-}]$ $= 2 C = 2 \times 0.5 \times 10^{- 5} M = 10^{- 5} M$

$p O H = - l o g [O H^{-}] p O H = - l o g (10^{- 5}) = 5 p H + p O H = 14 p H = 14 - p O H = 14 - 5 p H = 9$

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pH the Power of H

Standard XI Chemistry

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Consider a strong base, Ca(OH)2 in a solution having concentration of 0.5×10−5 M. The pH of the given solution of Ca(OH)2 is :

The correct option is C 9Given, [Ca(OH)2]initial=0.5×10−5 M=C Since it is a strong base, it ionizes completely. Then , Ca(OH)2(aq)⇌Ca2+(aq.)+2OH−(aq.)Initial: C 0 0Equilibrium: 0 C 2C [OH−] =2C=2×0.5×10−5 M=10−5 M pOH=−log[OH−]pOH=−log(10−5)=5pH+pOH=14pH=14−pOH=14−5pH=9

Consider a strong base, $C a (O H)_{2}$ in a solution having concentration of $0.5 \times 10^{- 5} M$ . The $p H$ of the given solution of $C a (O H)_{2}$ is :