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Question

Consider a system having 'm' resource of the same type. The resources are shared by 3 processes P, Q, R which have peak time demands 5, 6, 8 respectively. The minimum value of 'm' that ensures the deadlock will never occur is

A
18
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B
17
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C
15
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D
16
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Solution

The correct option is B 17
(D)
Minimum resources that are required to avoid deadlock
= (m11)+(m21)++(my1)+1
Where, m = resources required by process, y = number of processes.
So, number of resources that ensure the deadlock will never occur is
= ( 5 -1 ) + ( 6 - 1) + ( 8- 1)+1
= 4 + 5 + 7 +1
= 17

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