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Question

Consider a system of two identical particles. One of the particle is at rest and other has an acceleration a. The centre of mass has an acceleration

A
zero
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B
12a
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C
a
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D
2a
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Solution

The correct option is B 12a
Two identical particles
One of the particle=u=0
Acceleration=a
The centre of mass
s=ut+12at2(u=0)
Centre of mass=12a(t=1)

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