CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Consider a tank made of glass (refractive index 1.5) with a thick bottom. It is filled with a liquid of refractive index μ. A student finds that, irrespective of what the incident angle i (see figure) is for a beam of light entering the liquid, the light reflected from the liquid glass interface is never completely polarized. For this to happen, the minimum value of μ is:


A
53
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
53
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
35
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
43
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 35

For any reflected rays not to completely get polarized,

ic<ib(1)

According to Brewster's law,

tanib=1.5μ

sinib=1.5μ2+(1.5)2

The critical angle between air and the liquid is given by,

sinic=1μ

From (1), sinic<sinib

1μ<1.5μ2+(1.5)2

μ2+(1.5)2<1.5×μ

μ2+(1.5)2<(μ×1.5)2

μ>35

Therefore, the minimum value of μ should be 35

Hence, option (B) is correct.

flag
Suggest Corrections
thumbs-up
18
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Light as Wave
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon