Question

Consider a tightly wound 100 turn coil of radius 10 cm, carrying a current of 1A. What is magnitude of the magnetic field at the center of the coil ?

Answer 1

Number of turns in the coil $N=100$
Radius of coil $r=0.1$ m
Current flowing in the coil $I=1$ A
Magnetic field at the center of the coil $B=\frac{{\mu }_{o}IN}{2r}$
$\therefore$ $B=\frac{4\pi \times {10}^{-7}\times 1\times 100}{2\times 0.1}$
$⟹$ $B=6.28\times {10}^{-4}$ T