Question

Consider a transmission line of characteristic impedance 50 ohm. Let it be terminated at one end by (+j50) ohm. The VSWR produced by it in the transmission line will be

Answer 1

Ans : (c)

Reflection coefficient = $\Gamma =\frac{Z_L-Z_0}{Z_L+Z_0}$

$\Gamma =\frac{j50-50}{j50+50}=\frac{-50+j50}{50+j50}$

$\left|\Gamma \right|=\frac{\sqrt{(50{)}^2+(50{)}^2}}{\sqrt{(50{)}^2+(50{)}^2}}=1$

VSWR = $\frac{1+\left|\Gamma \right|}{1-\left|\Gamma \right|}=\frac{1+1}{1-1}=\frac{2}{0}=\infty$