Question

Consider a trapezium $ABCD$ with $AB=8cm,BC=AD=5cm,$ and $CD=2cm$. It has an altitude $CE=8cm$ on line $AB$. Find the area of the trapezium.

• A. $50c{m}^2$
• B. $40c{m}^2$
• C. $25c{m}^2$
• D. $10c{m}^2$

Answer 1

Answer: (B)

$40c{m}^2$

Given :

In $ABCD$, $AB=8cm,BC=AD=5cm,$ and $CD=2cm$

And altitude $CE=8cm$ which is the height of trapezium.

Area of trapezium $=\frac{(a+b)}{2}h$

$=\frac{8+2}{2}\times 8$

$=40c{m}^2$.

Hence, option B is correct.