Consider a triangle ABC. CC1 and BB1 are the medians drawn through angular points B and C respectively and 'G' is the centroid of ΔABC. If the points A, C1, G and B1 are concyclic, then
A
3b2=a2+c2
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B
2a2=b2+c2
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C
3c2=a2+b2
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D
None of these
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Solution
The correct option is D None of these c2=b2+a2−2abcosC=b2+a2−2ab⎛⎜
⎜⎝ba2⎞⎟
⎟⎠=b2+a2−4b2∴c2=a2−3b2⇒3b2=a2−c2