Consider a △ABC whose sides a,b and c are such that a2,b,c2 are in G.P., then which of the following statement(s) is/are correct ?
(where a,b,c are sides of △ABC opposite to ∠A,∠B and ∠C respectively)
A
sinA=bsinC
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B
sinB=csinA
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C
sinC=asinB
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D
sinB=asinC
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Solution
The correct option is DsinB=asinC Given : a2,b,c2 are in G.P. ⇒b2=a2c2⇒b=ac⇒bc=a⋯(i)
or ba=c⋯(ii)
From sine rule, we have bc=sinBsinC
and ba=sinBsinA
Putting the above values in (i) and (ii), we get sinB=asinC or sinB=csinA