Consider a two dimensional array A[20][10]. Assume 4 words per memory cell, the base address of array A is 100, elements are stored in row-major order and first element is A[0][0].What is the address of A[11][5]?
A
575
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B
560
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C
570
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D
460
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Solution
The correct option is B 560 Element A[11][0] is stored at
“Base Address +11∗10∗4"
which is
"Base Address + 440" = 540.
So, A[11][5] is stored at 540+5∗4=560.