Question

Consider a two particle system with the particles having masses \(m_1 and m2\) . If the first particle is pushed towards the centre of mass through a distance 'd', by what distance should the second particle be moved, so as to keep the centre of mass at the same position?

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

Let '$△x_1$' be the displacement of first particle = d

Let '$△x_2$' be the displacement of second particle in opposite direction to the displacement of first particle = - $△x_2$

$\therefore$ As $△x_{cm}=0\Rightarrow \frac{m_1△x_1+m_2△x_2}{m_1+m_2}$

$\Rightarrow m_1△x_1+m_2(-△x_2)=0$

$\Rightarrow △x_2=\frac{m_{1}d}{m_2}$