Consider a unity feedback system, as in the figure shown, with an integral compensator Ks and open-loop transfer function
G(s)=1s2+3s+2
where K>0 . The positive value of K for which there are exactly two poles of the unity feedback system on the jω is equal to
Y(s)X(s)=Ks3+3s2+2s+K
Two poles of this system lie on the jω axis when the system is marginally stable.
kmar=3×2=6