Consider an amplifier circuit shown in the figure below:
The voltage gain of the circuit is equal to (Assume VT=25 mV and VBE=0.7V)
A
-200
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B
-400
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C
415
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D
-210
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Solution
The correct option is B -400 Applying KVL in base emitter loop, we get, IB=10−0.7372 kΩ=25μA To draw the small signal we need to calculate rπ ∴rπ=VTTBDC=25×10−325×10−6=103Ω