Consider an electron (m=9.1×10−31kg) confined by electrical forces to move between two rigid walls separated by 1.0×10−9metre, which is about five atomic diameter. The quantised energy value for the lowest stationary state is :
A
12×10−20J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6.0×10−20J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6.0×10−18J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B6.0×10−20J Hence, option (B) is correct.