Consider an electron oscillating with a frequency of 30 MHz. The electromagnetic radiation emitted will have a wavelength equal to

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 10m
$λ = \frac{C}{f} = \frac{3 \times 10^{8}}{30 \times 10^{6}} = 10 m$

Suggest Corrections

Similar questions

Q. When electromagnetic radiation of wavelength

300 n m

falls on the surface of sodium, electrons are emitted with a kinetic energy of

1.68 \times 10^{5} J m o l^{- 1}

. What is the maximum wavelength that will cause a photoelectron to be emitted?

Radio station broadcasts on a frequency of 1368kHz. Calculate the wavelength and wave number of the electromagnetic radiation emitted by the transmitter

When electromagnetic radiation of wavelength 300 nm falls on the surface of sodium, electrons are emitted with a kinetic energy of 1.68×105J mol−1. What is the maximum wavelength that will cause a photoelectron to be emitted?

Q. When electromagnetic radiation at wavelength 300nm falls on the surface of sodium, electrons are emitted with a kinetic energy of

1.68 \times 10^{5} J {m o l}^{- 1}

. What Is the minimum energy needed to remove an electron from sodium?

Q. The ratio of energy to frequency of a radiation emitted by an electron is equal to :

Join BYJU'S Learning Program

Consider an electron oscillating with a frequency of 30 MHz. The electromagnetic radiation emitted will have a wavelength equal to

The correct option is D 10mλ=Cf=3×10830×106=10m

The correct option is D 10m
$λ = \frac{C}{f} = \frac{3 \times 10^{8}}{30 \times 10^{6}} = 10 m$