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Question

Consider an elevator moving downwards with an acceleration a. The force exerted by a passenger of mass m on the floor of the elevator:

A
ma
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B
mamg
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C
mgma
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D
mg+ma
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Solution

The correct option is B mgma
the force exerted by the man on the floor is the normal and its reaction is being exerted on the man itself
Applying the first law of motion
MgN=Ma
N=M(ga)

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