Consider an elevator moving downwards with an acceleration a. The force exerted by a passenger of mass m on the floor of the elevator:
A
ma
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B
ma−mg
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C
mg−ma
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D
mg+ma
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Solution
The correct option is Bmg−ma the force exerted by the man on the floor is the normal and its reaction is being exerted on the man itself Applying the first law of motion Mg−N=Ma N=M(g−a)