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Question

Consider an ideal gas that occupies 2.50 dm3 at a pressure of 3 bar. If the gas is compressed isothermally at a constant pressure Pext, so that the final volume becomes 0.5 dm3. Calculate the value of Pext and the work done respectively.
Given: 1 bar.L = 100 J

A
20 bar and 1000 J
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B
15 bar and 3000 J
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C
30 bar and 1500 J
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D
10 bar and 3750 J
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Solution

The correct option is B 15 bar and 3000 J
For isothermal process of an ideal gas,
we can use, PV = constant.
So, P1V1=P2V2
where P1 = 3 bar
V1=2.5 dm3
V2=0.5 dm3
using these values to find P2,
P2 = 15 bar
work done for irreversible process is
w = PextΔV
w = 15×(0.52.5) bar.dm3
=3000 J

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