Question

Consider an Indian rubber cube having modulus of rigidity of $2\times {10}^{7}dynec{m}^{-2}$ and of side $8cm$. If one side of the rubber is fixed, while a tangential force equal to the weight of $300kg$ is applied to the opposite face, then find out the shearing strain produced and distance through which the strain side moves.

Answer 1

Shear modulus $=2\times {10}^{7}dynec{m}^{-2}=2\times {10}^{2}N/cm$

$a=8c{m}^2$

$F=300\times 10=3000N$

$\frac{3000N}{64c{m}^s}=2\times {10}^{2}N/cm$ .strain

$Strain=\frac{3000}{64\times 200}=\frac{15}{64}=0.234$

$\frac{\Delta l}{l}=0.234$

$\Delta l=(0.234\times 8)cm$

$\Delta l=4872cm$