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Question

Consider an optical communication system operating at l~800 nm. Suppose, only 1% of the optical source frequency is the available channel bandwidth for optical communication. How many channels can be accommodated for transmitting audio signals requiring a bandwidth of 8 kHz

A
4.8 x 108
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B
48
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C
6.2 x 108
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D
4.8 x 105
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Solution

The correct option is A 4.8 x 108

Optical source frequency f = cλ
= 3×108800×109=3.8×1014Hz
Bandidth of channel (1 % of above) = 3.8 × 1012 Hz
Number of channel = (Total bandwidth of channelBandwidth needed per channel)
(a) Number of channels for audio signal
= (3.8×1012)8×103 ~4.8 ×108


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