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Question

# Consider Statement-I: (p∧∼q)∧(∼p∧q) is fallacy Statement-II: (p→q)↔(∼q→∼p) is tautology

A
Statement-I is true; Statement-II is true; Statement-II is a correct explanation for Statement-I.
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B
Statement-I is true; Statement-II is true; Statement-II is not a correct explanation for Statement-I.
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C
Statement-I is true; Statement-II is false.
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D
Statement-I is false; Statement-II is true.
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Solution

## The correct option is B Statement-I is true; Statement-II is true; Statement-II is not a correct explanation for Statement-I.Statement-II: (p→q)↔(∼q→∼p) ⇒(p→q)↔(p→q) ∴ It is always true Statement-I: (p∧∼q)∧(∼p∧q) ⇒p∧∼q ∧∼p∧q ⇒p∧∼p ∧∼q∧q ⇒f∧f ⇒f ∴ It is true Clearly, Statement-II is not a correct explanation for Statement-I.

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