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Question

Consider f: R+ ā†’ [4, āˆž) given by f(x) = x2 + 4. Show that f is invertible with the inverse fāˆ’1 of given f by, where R+ is the set of all non-negative real numbers.

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Solution

f: R+ ā†’ [4, āˆž) is given as f(x) = x2 + 4.

One-one:

Let f(x) = f(y).

āˆ“ f is a one-one function.

Onto:

For y āˆˆ [4, āˆž), let y = x2 + 4.

Therefore, for any y āˆˆ R, there exists such that

.

āˆ“ f is onto.

Thus, f is one-one and onto and therefore, fāˆ’1 exists.

Let us define g: [4, āˆž) ā†’ R+ by,

āˆ“

Hence, f is invertible and the inverse of f is given by


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