Consider following frequency distribution.
Class Intervals $0 - 10$ $10 - 20$ $20 - 30$ $30 - 40$
Frequency $8$ $10$ $12$ $15$
Arithmetic mean $=$ ?

39.65

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22.55

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32.55

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23.56

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Solution

The correct option is C $22.55$

Class Intervals

0−10

10−20

20−30

30−40

Frequency(f)

8

10

12

15

Class mark ( mid points= x)

5

15

25

35

Fx

40

150

300

525

Mean = summation of fx / summation of f

= 1015/ 45

= 22.55

Suggest Corrections

Class-interval	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$	$50 - 60$
Frequency	$7$	$14$	$28$	$26$	$16$	$9$

Class Intervals	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$
Frequency	$8$	$10$	$12$	$15$

Class interval	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$
Frequency	$5$	$18$	$15$	$p$	$6$

Class interval:	0−10	10−20	20−30	30−40	40−50
Frequency:	9	12	15	10	14