Question

Consider following reaction :
$A\stackrel{O_3/Zn,H_{2}O}{\to }(C{H}_3{)}_{2}CO+HCHO+\underset{CHO}{\stackrel{CHO}{|}}$
Thus, A is

• A. $(C{H}_3{)}_{2}CHCH=CHCH=C{H}_2$
• B. $(C{H}_3{)}_{2}C=CHCH=C{H}_2$
• C. $C{H}_{3}CH=CHCH=CHCH=C{H}_2$
• D. none of these

Answer 1

The correct option is A $(C{H}_3{)}_{2}CHCH=CHCH=C{H}_2$

A $⟶(C{H}_3{)}_{2}CHCH=CHCH=C{H}_2$

$C{H}_3$ $CHO$ $O$

$\underset{\left(A\right)}{(C{H}_3{)}_{2}CHCH}=CHCH=C{H}_2\underset{Zn/H_{2}O}{\overset{O_3}{\to }}\stackrel{|}{\underset{|}{C}}=O+\stackrel{|}{CHO}+H-\stackrel{||}{C}-H$

$C{H}_3$

Ozonolysis of A gives three product. It is a type of $1,3$ Dipolar cyclo-addition. It is a property of an alkene.