Consider following reactions in equilibrium with equilibrium concentration $0.01 M$ of every species.
(I) $P C l_{s} (g) ⇌ {P C l}_{3} (g) + C l_{2} (g)$
(ii) ${2 H I (g) ⇋ H}_{2} (g) + l_{2} (g)$
(iii) $N_{2} (g) + 3 H_{2} (g) ⇋ {2 N H}_{3} (g)$
Extent of the reactions taking place is:

l I I > l l > l

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l < l l < l l l

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l l < l l l < l

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l l l < l < l l

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Solution

The correct option is B $l I I > l l > l$
Solution:- (B) $I < I I < I I I$
$Δ n_{g} = n_{P} - n_{R}$
${P {C l}_{5}}_{(g)} ⇌ {P {C l}_{3}}_{(g)} + {C l}_{2}_{(g)}$
$Δ n_{g} = (1 + 1) - 1 = 2 - 1 = 1$
$2 {H I}_{(g)} ⇋ {H_{2}}_{(g)} + {I_{2}}_{(g)}$
$Δ n_{g} = (1 - 1) - 2 = 2 - 2 = 0$
${N_{2}}_{(g)} + 3 {H_{2}}_{(g)} ⇋ 2 {N H_{3}}_{(g)}$
$Δ n_{g} = 2 - (1 + 3) = 2 - 4 = - 2$
$∴$ Order of extent of given reaction will be-
$I I I > I I > I$

Suggest Corrections

Similar questions

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)

2 H I (g) ⇌ H_{2} (g) + I_{2} (g)

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P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)

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