You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Polarity and Dipole Moments

Consider foll...

Question

Consider following three halides:
(I) $C H_{3} - C H_{2} - C l$ ;
(II) $C H_{2} = C H - C l$ ;
(III) $C_{6} H_{5} C l$
Arrange $C - C l$ bond length of these compounds in decreasing order.

I > I I > I I I

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

I > I I I > I I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I I I > I I > I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I I > I I I > I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $I > I I > I I I$
I > II > III because

Suggest Corrections

Similar questions

Q. The decreasing order of rate of

S_{N} 2

reaction for given compounds is:

C H_{3} - C l

C H_{3} - C | | O - C H_{2} - C l

C H_{3} - C H | C H_{3} - C H_{3} - C l

C H_{3} - C H_{2} - C l

(I) (II) (III) (IV)

$C H_{3} O - C H = C H - N O_{2}$	$I$
$C H_{2} = C H - N O_{2}$	$I I$
$C H_{2} = C H - C l$	$I I I$
$C H_{2} = C H_{2}$	$I V$

Which of the following is the correct order of

C = C

bond lengths among these compounds?

Q. Arrange the following compounds in the order of decreasing tendency towards

S N_{2}

reaction.

C H_{3} C H_{2} C H_{2} C l . . . . . . . . . (i)

C H_{3} C H_{2} C H C l C H_{3} . . . . . . . (i i)

(C H_{3})_{2} C H C H_{2} C l . . . . . . . . (i i i)

(C H_{3})_{3} C - C l . . . . . . . . . . (i v)

Arrange the following: $C H_{3} C H_{2} C H_{2} C l (I), C H_{3} C H_{2} C H C l C H_{3} (I I) {(C H_{3})}_{2} C H C H_{2} C l (I I I) a n d {(C H_{3})}_{3} C - C l (I V)$ in order of decreasing tendency towards $S N^{2}$ reaction

Q. Arrange the following compounds in decreasing order of acidity -
(i)

H C \equiv C H

(ii)

H_{2} C = C H_{2}

(iii)

H_{3} C - C H_{3}

Join BYJU'S Learning Program

Consider following three halides:(I) CH3−CH2−Cl ;(II) CH2=CH−Cl ;(III) C6H5ClArrange C−Cl bond length of these compounds in decreasing order.

The correct option is C I>II>IIII > II > III because

Consider following three halides:
(I) $C H_{3} - C H_{2} - C l$ ;
(II) $C H_{2} = C H - C l$ ;
(III) $C_{6} H_{5} C l$
Arrange $C - C l$ bond length of these compounds in decreasing order.

The correct option is C $I > I I > I I I$
I > II > III because