Solving Linear Differential Equations of First Order
Consider I1=∫...
Question
Consider I1=π/4∫0ex2dx,I2=π/4∫0exdx, I3=π/4∫0ex2cosxdx,I4=π/4∫0ex2sinxdx
Statement 1:I2>I1>I3>I4
Statement 2: For x∈(0,π4),x>x2 and cosx>sinx
A
Both statements 1 and 2 are true but statement 2 is not the correct explanation of statement 1.
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B
Statement 1 is true but statement 2 is false.
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C
Both statements 1 and 2 are true and statement 2 is the correct explanation of statement 1.
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D
Statement 1 is false but statement 2 is true.
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Solution
The correct option is A Both statements 1 and 2 are true but statement 2 is not the correct explanation of statement 1. For x∈(0,π4) x>x2⇒ex>ex2⇒I2>I1
Also, 1>cosx>sinx,∀x∈(0,π4)⇒ex2>ex2cosx>ex2sinx⇒I1>I3>I4∴I2>I1>I3>I4