Question

Consider molecule of $C{H}_2=S{F}_4$. Which of the following options is/are incorrect?

• A. 6 atoms are present in vertical plane passing through C and S
• B. 5 atoms are present in horizontal plane passing through C and S
• C. $\pi$bond is formed by the overlapping of Py of C and $d_{(x^2-y^2)}$ of S atom
• D. horizontal bond angle FSF is more than horizontal bond angle FSF in $S{F}_4$

Answer 1

Answer: (C), (D)

The correct options are
C $\pi$bond is formed by the overlapping of Py of C and $d_{(x^2-y^2)}$ of S atom
D horizontal bond angle FSF is more than horizontal bond angle FSF in $S{F}_4$

C D
lone pair -bond pair repulsion is more than B.P - B.P repulsion so FSF angle is more in $C{H}_2=S{F}_4$, than in $S{F}_4.$

$P\pi -d\pi$ bond