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Question

Consider P is a point on y2=4ax, if the normal at P, the axis and the focal radius of P form an equilateral triangle. Then coordinates of P are

A
(4a,4a)
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B
(3a,23a)
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C
(a3,2a3)
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D
(3a,23a)
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Solution

The correct option is C (a3,2a3)
Let P be (at2,2at) and PN be normal
32SP=PM, where M is foot of perpendicular from P upon axis of parabola
32(at2+a)=2at
3t2+3=4t
3t24t+3=0
3t23tt+3
3t(t3)1(t3)=0
(t3)(3t1)=0
t=3 or t=13
So, P is (3a,23a) or (a3,2a3)


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