Question

Consider points $A(-1,3),B(-1,2)$. Find point $P$ which divides $AB$ externally in $\frac{5}{4}$.

• A. $(9,-22)$
• B. $(-1,2)$
• C. $(-1,-2)$
  
• D. $(9,22)$

Answer 1

Answer: (C)

$(-1,-2)$

Let point P be (x,y)

$x=\frac{5\times (-1)-4\times (-1)}{5-4}x=\frac{-5+4}{1}x=-1y=\frac{5\times \left(2\right)-4\times \left(3\right)}{5-4}y=\frac{10-12}{1}y=-2\therefore P=(-1,-2)$