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Question

Consider that a d6 metal ion (M2+) forms a complex with aqua ligands, and the spin only magnetic moment of the complex is 4.9BM. The geometry and the crystal field stabilization energy of the complex is:


A

Tetrahedral and -0.6t

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B

Tetrahedral and -1.6t+1P

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C

Octahedral and -1.60

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D

Octahedral and -2.40+2P

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Solution

The correct option is A

Tetrahedral and -0.6t


Explanation for correct option:

(A) tetrahedral and -0.6t

  1. As it is given that spin only magnetic moment of the complex is 4.9BM so the number of the unpaired electron must be 4.
  2. The crystal field splitting for the tetrahedral complex is :
  3. The crystal field splitting energy for the tetrahedral complex is: CFSE=-0.6×3t+0.4×3t=-1.8t+1.2t=-0.6t

Explanation for incorrect options:

(B) Tetrahedral and -1.6t+1P

  1. As it can be observed from the calculations done for crystal field splitting that the crystal field energy for the tetrahedral complex is-0.6t.
  2. Hence, the present option is incorrect.

(C) Octahedral and -1.60

  1. The crystal field splitting for the tetrahedral complex is:
  2. The crystal field splitting energy for the tetrahedral complex is: CFSE=-0.4×4O+0.6×2O=1.6+1.2o=-0.4o
  3. The calculated crystal field energy and geometry of the complex do not coincide with the given option.

(D) Octahedral and -2.40+2P

  1. As it can be observed from the calculations done for crystal field splitting that the crystal field energy for the octahedral complex is-0.4o.
  2. Hence, the present option is incorrect.

Hence option (A) is correct, The geometry of the given complex is tetrahedral and the crystal field splitting energy is -0.6t.


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