Consider the acidity of the carboxylic acids:
(i) $C_{6} H_{5} C O O H$ (ii) $O - N O_{2} C_{6} H_{4} C O O H$
(iii) $p - N O_{2} C_{6} H_{4} C O O H$ (iv) $m - N O_{2} C_{6} H_{4} C O O H$
Which of the following order is correct?

(i) > (ii) > (iii) > (iv)

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(ii) > (iv) > (iii) > (i)

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(ii) > (iv) > (i) > (iii)

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(ii) > (iii) > (iv) > (i)

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Solution

The correct option is D (ii) > (iii) > (iv) > (i)

$\to N O_{2}$ at o-position stabilizes by both - I and - R
$\to N O_{2}$ at p-position stabilizes only by - R
$\to N O_{2}$ at m-position stabilizes by - I only

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Similar questions

Consider the acidity of carboxylic acids i.Ph - COOH ii. o - NO₂ C₆H₄COOH iii. p - NO₂ C₆H₄COOHiv. m - NO₂ C₆H₄COOH which of the following order is correct

Order of decreasing acidity of the following is

(I) HCOOH

(II) ${C H}_{3} C O O H$

(III) ${C l}_{2} C H C O O H$

(IV) ${C F}_{3} C O O H$

Q. The decreasing order of acidic character of the following is:
I.

C H_{3} S H

II.

C H_{3} O H

III.

H_{2} O

IV. EtOH

Order of decreasing acidity of

$(i) H C O O H (i i) C H_{3} C O O H (i i i) C l_{2} C H C O O H (i v) C F_{3} C O O H i s$

Q. Consider the acidity of the carboxylic acids.
(i)

P h C O O H

(ii) o-

N O_{2} C_{6} H_{4} C O O H

(iii) p -

N O_{2} C_{6} H_{4} C O O H

(iv) m -

N O_{2} C_{6} H_{4} C O O H

which of the following order is correct ?

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Consider the acidity of the carboxylic acids: (i) C6H5COOH (ii) O−NO2C6H4COOH (iii) p−NO2C6H4COOH (iv) m−NO2C6H4COOH Which of the following order is correct?

The correct option is D (ii) > (iii) > (iv) > (i) →NO2 at o-position stabilizes by both - I and - R →NO2 at p-position stabilizes only by - R →NO2 at m-position stabilizes by - I only

Consider the acidity of the carboxylic acids:
(i) $C_{6} H_{5} C O O H$ (ii) $O - N O_{2} C_{6} H_{4} C O O H$
(iii) $p - N O_{2} C_{6} H_{4} C O O H$ (iv) $m - N O_{2} C_{6} H_{4} C O O H$
Which of the following order is correct?

The correct option is D (ii) > (iii) > (iv) > (i)

$\to N O_{2}$ at o-position stabilizes by both - I and - R
$\to N O_{2}$ at p-position stabilizes only by - R
$\to N O_{2}$ at m-position stabilizes by - I only