Question

Consider the alkane- ${\left({CH}_3\right)}_{2}CH{CH}_{2}CH\left(C_2{H}_5\right)CH\left({CH}_3\right){CH}_3$
(i) What is its molecular formula?
(ii) How many $1^o,2^o,3^o,4^o$ carbon atom are present.
(iii) State the number of methyl, methylene and methane group in the alkane.

Answer 1

$\underset{1^0}{C{H}_3}-\stackrel{3^0-}{\underset{\underset{1^0-}{C{H}_3}}{\underset{|}{CH}}}-\underset{2^0-}{C{H}_2}-\stackrel{\stackrel{1^0-}{2^{0}C{H}_5}}{\stackrel{|}{\underset{3^0-}{CH}}}-\underset{1^0-}{\underset{C{H}_3}{\underset{|}{\stackrel{3^0-}{CH}}}}-\underset{1^0-}{C{H}_3}$

Molecular formula $\equiv C_{10}{H}_{22}$

$\begin{array}{c}{3}^o-carbon=\sqrt{2}\\ 2^o-carbon=2\\ 1^o-carbon=0\end{array}|\begin{array}{c}-C{H}_3\Rightarrow methyl\left(\sqrt{2}\right)\\ -C{H}_2\Rightarrow Methylene\left(2\right)\\ Methane\Rightarrow zero\end{array}$