Question

Consider the barometer shown in figure. Density of mercury is $\rho$. A small hole is made at point $S$ as shown. The mercury comes out from this hole with speed $v$ equal to:

• A. $\sqrt{2gh}$
• B. $\sqrt{2gH}$
• C. $\sqrt{2g(H-h)}$
• D. None of the above

Answer 1

Answer: (D)

Given,

The density of the mercury is $\rho$
Speed = v
$v$$

According to Bernoulli's equation

$\rho gh+{\rho }_0={\rho }_0+\frac{1}{2}\rho {\text{v}}^2$ From the equation we can say

$v=\sqrt{2gh}$

Hence, option A is correct.