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Question

Consider the Boolean expression:f(A,B,C,D)=¯¯¯¯¯¯¯¯AB+¯¯¯¯A ¯¯¯¯C ¯¯¯¯¯D+¯¯¯¯A ¯¯¯¯B D+¯¯¯¯¯¯¯¯AB C ¯¯¯¯¯D
then the minimised expression of f(A,B,C,D) is equal to

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Solution

f(A,B,C,D)=¯¯¯¯¯¯¯¯AB+¯¯¯¯A ¯¯¯¯C ¯¯¯¯¯D+¯¯¯¯A ¯¯¯¯B D+¯¯¯¯¯¯¯¯AB C ¯¯¯¯¯D=¯¯¯¯¯¯¯¯AB(1+C¯¯¯¯¯D)+¯¯¯¯A ¯¯¯¯C ¯¯¯¯¯D+¯¯¯¯A ¯¯¯¯BD=¯¯¯¯A+¯¯¯¯B+¯¯¯¯A ¯¯¯¯C ¯¯¯¯¯D+¯¯¯¯A ¯¯¯¯BD=¯¯¯¯A(1+¯¯¯¯C ¯¯¯¯¯D+¯¯¯¯B ¯¯¯¯¯D)+¯¯¯¯B=¯¯¯¯A+¯¯¯¯B=¯¯¯¯¯¯¯¯AB

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