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Question

# Consider the Boolean expression:f(A,B,C,D)=Â¯Â¯Â¯Â¯Â¯Â¯Â¯Â¯AB+Â¯Â¯Â¯Â¯A Â¯Â¯Â¯Â¯C Â¯Â¯Â¯Â¯Â¯D+Â¯Â¯Â¯Â¯A Â¯Â¯Â¯Â¯B D+Â¯Â¯Â¯Â¯Â¯Â¯Â¯Â¯AB C Â¯Â¯Â¯Â¯Â¯D then the minimised expression of f(A,B,C,D) is equal to

A
¯¯¯¯¯¯¯¯AB
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B
¯¯¯¯¯¯¯¯BC
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C
¯¯¯¯¯¯¯¯¯CD
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D
¯¯¯¯¯¯¯¯AC
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Solution

## The correct option is A ¯¯¯¯¯¯¯¯ABf(A,B,C,D)=¯¯¯¯¯¯¯¯AB+¯¯¯¯A ¯¯¯¯C ¯¯¯¯¯D+¯¯¯¯A ¯¯¯¯B D+¯¯¯¯¯¯¯¯AB C ¯¯¯¯¯D=¯¯¯¯¯¯¯¯AB(1+C¯¯¯¯¯D)+¯¯¯¯A ¯¯¯¯C ¯¯¯¯¯D+¯¯¯¯A ¯¯¯¯BD=¯¯¯¯A+¯¯¯¯B+¯¯¯¯A ¯¯¯¯C ¯¯¯¯¯D+¯¯¯¯A ¯¯¯¯BD=¯¯¯¯A(1+¯¯¯¯C ¯¯¯¯¯D+¯¯¯¯B ¯¯¯¯¯D)+¯¯¯¯B=¯¯¯¯A+¯¯¯¯B=¯¯¯¯¯¯¯¯AB

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Inequations I
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