Consider the capacitors A and B shown in the figure. The capacitor A has a charge +q on it whereas B is uncharged. The charge appearing on the capacitor B a long time after the switch is closed is:

zero

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\frac{q}{2}

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Solution

The correct option is B $\frac{q}{2}$
When the switch is closed , the charge, the charge on capacitor 'A' will move cross capacitor 'B' since there is no charge on capacitor 'B'. The will develop on capacitor on capacitor 'B' as long the switch is closed until both capacitor aquire equal charge . therefore the charge on capacitor 'B' will be $\frac{q}{2}$

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