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Question

Consider the cell potentials EMg2+|Mg = 2.37V and EFe2+|Fe = 0.04V . The best reducing agent among the above would be:

A
Mg
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B
Fe3+
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C
Mg2+
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D
Fe
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Solution

The correct option is C Mg
E0Mg2+/Mg=2.37 V
E0Fe2+/Fe=0.04 V
As reduction potential of Fe2+ is higher that that of Mg2+
in term of oxidation potential
E0Mg2+/Mg=2.37 V
E0Fe2+/Fe=0.04 V
strong reducing agent reduce other species oxidise itself should have high oxidation potential. As Mg has high oidation potential than Fe.
Mg will act as strong reducing agent.

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