Consider the cell potentials E∘Mg2+|Mg = −2.37V and E∘Fe2+|Fe = −0.04V . The best reducing agent among the above would be:
A
Mg
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B
Fe3+
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C
Mg2+
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D
Fe
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Solution
The correct option is CMg E0Mg2+/Mg=−2.37 V E0Fe2+/Fe=−0.04 V As reduction potential of Fe2+ is higher that that of Mg2+ in term of oxidation potential E0Mg2+/Mg=2.37V E0Fe2+/Fe=0.04V ⟹ strong reducing agent reduce other species ⟹ oxidise itself ⟹ should have high oxidation potential. As Mg has high oidation potential than Fe. ∴Mg will act as strong reducing agent.