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Question

Consider the cell:
Zn|Zn2+(aq)(1.0M)||Cu2+(aq)(1.0M)||Cu
The standard reduction potential are 0.350 V for Cu2+(aq)+2eCu and -0.763 V for Zn2+(aq)+2eZn.
The EMF (in V) of the cell is ( write your answer as nearest integer) :

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Solution

EMF of the cell = EcathodeEanode
=ECu2+|CuEZn2+|Zn
=0.350(0.763)=1.113V

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