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Inductive Reactance

Consider the ...

Question

Consider the circuit given below:
The value of input resistance $R_{i n}$ is _____
102.38

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Solution

The correct option is A 102.38
$500 k I_{B} + 0.7 + 1 k (I_{B} + I_{C}) = 12$

$I_{C} = 100 I_{B}$

$I_{E} = 101 I_{B}$

from here $I_{B} = 18.80 μ A$

$r_{π} = β \times \frac{V_{T}}{I_{C}} = \frac{V_{T}}{I_{B}} = \frac{26}{18.8} k Ω = 1.383 k Ω$

$R_{i n} = r_{π} + (1 + β) R_{E}$

$= 1.383 k + 101 \times 1 k = 102.383 k Ω$

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