Consider the circuit shown below: If VBE=0.7V, then the voltage v0 is (Assume I∞ is negligible)
A
0.5 V
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B
0.4 V
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C
0.7 V
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D
0.6 V
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Solution
The correct option is B 0.4 V
The Thevenin's equivalent circuit between the terminals A and ground is Vth=−5V Rth=(10kΩ)||(10kΩ) =5kΩ I1=−5+10−0.74200+50001+49 I1=4.34300=1mA I2=4950mA I3=I2×(β1+β)